The sum of the squares of the first ten natural numbers is, 1^2 + 2^2 + … + 10^2 = 385

The square of the sum of the first ten natural numbers is, (1 + 2 + … + 10)^2 = 55^2 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

– Project Euler Problem 6

function getDiff(N::UInt64, power::UInt8)
        atoms::Array{UInt64,1} = collect(1:N);
        powerOfSum::UInt64 = sum(atoms)^power;
        sumOfPowers::UInt64 = sum(map(x -> x^power, atoms));
        difference::UInt64 = powerOfSum - sumOfPowers;
        return difference

end



function parseARGS()
        if isempty(ARGS)
                N::UInt64 = 100;
                power::UInt8 = 2;
        else
                N = tryparse(UInt64,ARGS[1]);
                power = tryparse(UInt8,ARGS[2]);
        end
        return N,power
end

function main()
        N,power = parseARGS()
        difference = getDiff(N,power);
        println(difference);
end

main()

$ julia ProjectEuler0006.jl 10 2
2640
  0.000042 seconds (22 allocations: 1.266 KiB)
  
$ julia ProjectEuler0006.jl 20 3
9216900
  0.000041 seconds (22 allocations: 1.422 KiB)

$ julia ProjectEuler0006.jl 100 2
25164150
  0.000043 seconds (22 allocations: 2.703 KiB)